And to make it even faster

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Sorry, I didn't see that you changed the code. In my robot I did it like that but it is more understandable with Math.pow(x, y).

Dsekercioglu (talk)‎14:55, 23 September 2017

Math.pow makes me think something like e^x, but it turned out to be polynomial.

Xor (talk)‎14:59, 23 September 2017
 
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