http://robowiki.net/w/index.php?action=history&feed=atom&title=Thread%3ATalk%3ASuperRamFire%2FBullet_Damage_Calculation%2FreplyThread:Talk:SuperRamFire/Bullet Damage Calculation/reply - Revision history2026-04-29T20:13:36ZRevision history for this page on the wikiMediaWiki 1.34.1http://robowiki.net/w/index.php?title=Thread:Talk:SuperRamFire/Bullet_Damage_Calculation/reply&diff=50392&oldid=prevBeaming: Reply to Bullet Damage Calculation2017-08-25T15:48:27Z<p>Reply to <a href="/wiki/Thread:Talk:SuperRamFire/Bullet_Damage_Calculation" title="Thread:Talk:SuperRamFire/Bullet Damage Calculation">Bullet Damage Calculation</a></p>
<p><b>New page</b></p><div>4 * BULLET_POWER is quite reasonable. Bullets hits are rare. A bot usually spends more energy firing to the enemy then by hits taken. Thus there is an extra reward/punishment multiplier when a bot get hit. If we remove this term from the equation than bullets with BULLET_POWER <= 1 would do no damage at all. Which would be strange.<br />
<br />
The real question why there is 2 * max(0, BULLET_POWER - 1) term. It gives an extra bonus to a high energy bullet. I guess it is the original authors way to reward slow moving (high energy) bullets which<br />
have less chance to hit a target. Why the reward is not continuous function of the BULLET_POWER is beyond me.</div>Beaming