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No you can't use average distance, as distance is used like x / distance, not x * distance.
- It is equal at infinity.
(8 / 5 + 1 + 8 / 11) / 3 = 1.109090909... (8 / 5 + 8 / 6.5 + 1 + 8 / 9.5 + 8 / 11) / 5 = 1.080029444...
- This goes closer to 1 every time I decrease the step size.
Dsekercioglu (talk)
