# Difference between revisions of "Thread:Talk:Bullet Shadow/Correct/Shadow depends on the bullet, not so on the wave/reply"

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− | I think the traditional shadow is 100%, the other shadows are 50%. And shadows cast from one bullet of yourself has no intersection, then the probability is independent, simplifying computation. And you don't need to actually cast the shadow when it happens, simply add the shadow when either one appears, and remove when bullet is destroyed. Further simplifies computation. | + | I think the traditional shadow is 100%, the other shadows are 50%. And shadows cast from one bullet of yourself has no intersection, then the probability is independent, simplifying computation. And you don't need to actually cast the shadow when it happens, simply add the shadow when either one appears, and remove when bullet is destroyed before shadow cast time. Further simplifies computation. |

## Latest revision as of 15:38, 29 June 2021

I think the traditional shadow is 100%, the other shadows are 50%. And shadows cast from one bullet of yourself has no intersection, then the probability is independent, simplifying computation. And you don't need to actually cast the shadow when it happens, simply add the shadow when either one appears, and remove when bullet is destroyed before shadow cast time. Further simplifies computation.