Difference between revisions of "User:Xor/Better MEA formula"
m (fix) |
m (fix) |
||
| Line 21: | Line 21: | ||
[[File:BetterMEABulletSpeed19_7.png]] | [[File:BetterMEABulletSpeed19_7.png]] | ||
| + | |||
| + | [[File:BetterMEAResultBulletSpeed19_7.png]] | ||
And for 19.7 wave speed — the result is mea = 0.414994rad, while the traditional one is 0.418172793rad. Pretty close though? (0.1821°) And you can do that for every wave! (until you hit the wall ;) ) | And for 19.7 wave speed — the result is mea = 0.414994rad, while the traditional one is 0.418172793rad. Pretty close though? (0.1821°) And you can do that for every wave! (until you hit the wall ;) ) | ||
| + | |||
| + | The best retreat angle for power 0.1 bullet is 1.360194211rad. (where moving away directly is 0rad) | ||
Revision as of 09:58, 18 September 2017
It seems that I made a mistake in previous calculation.
Correct calculation —
Consider a situation when you move orbital to the source of the wave with constant retreat angle (therefore constant lateral velocity and retreat velocity) —
where x is retreat velocity (the negative of advancing velocity)
However this formula is not greater than the traditional one ;/
Sorry guys.
Anyway, unlike traditional MEA which you can use for only one wave — this formula is capable of being used to maximize escape angle of every wave. Therefore it is still better — useful for wave surfers.
The best retreat angle (for power 3.0 bullet, considering only MEA) is — 1.152871236rad. (where moving away directly is 0rad)
And for 19.7 wave speed — the result is mea = 0.414994rad, while the traditional one is 0.418172793rad. Pretty close though? (0.1821°) And you can do that for every wave! (until you hit the wall ;) )
The best retreat angle for power 0.1 bullet is 1.360194211rad. (where moving away directly is 0rad)
