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Fragment of a discussion from User talk:Dsekercioglu/MEA
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You can't get escape angle higher than Pi/2 by the traditional formula simply because it is impossible.

If your formula can, it must be wrong.

Xor (talk)16:12, 24 September 2017
Found it!
It should be sin(a) / (v / 8 - cos(a) / 2).
Dsekercioglu (talk)16:15, 24 September 2017

The only correct formula to calculate the escape angle of orbital movement where <math>v_{retreat}</math> is not zero is using integral.

Anything else is wrong.

Xor (talk)16:18, 24 September 2017
 
I found a formula higher than Traditional MEA and this one should be correct.
Math.asin(Math.sin(angle) / (bulletSpeed / 8 - Math.cos(angle) / 2))
Dsekercioglu (talk)16:19, 24 September 2017

Anything higher than traditional formula is obviously wrong.

Xor (talk)16:21, 24 September 2017

I don't think that this one is wrong. I only added advancing velocity to the Traditional MEA which shouldn't break anything with the calculations.

Dsekercioglu (talk)16:26, 24 September 2017

No, advancing velocity makes distance not constant, therefore you mast use integral.

Xor (talk)00:44, 25 September 2017

I don't need integral. I can get the average distance.

distance - (advancingVelocity * timeToHit / 2) = bulletFloatTime - advancingVelocity / 2
Dsekercioglu (talk)11:08, 25 September 2017