And to make it even faster

You can't get escape angle higher than Pi/2 by the traditional formula simply because it is impossible.

If your formula can, it must be wrong.

Found it!

It should be sin(a) / (v / 8 - cos(a) / 2).

The only correct formula to calculate the escape angle of orbital movement where <math>v_{retreat}</math> is not zero is using integral.

Anything else is wrong.

I found a formula higher than Traditional MEA and this one should be correct.

Math.asin(Math.sin(angle) / (bulletSpeed / 8 - Math.cos(angle) / 2))

Anything higher than traditional formula is obviously wrong.

I don't think that this one is wrong. I only added advancing velocity to the Traditional MEA which shouldn't break anything with the calculations.

No, advancing velocity makes distance not constant, therefore you mast use integral.

I don't need integral. I can get the average distance.

distance - (advancingVelocity * timeToHit / 2) = bulletFloatTime - advancingVelocity / 2

No you can't use average distance, as distance is used like x / distance, not x * distance.

It is equal at infinity.

(8 / 5 + 1 + 8 / 11) / 3 = 1.109090909...
(8 / 5 + 8 / 6.5 + 1 + 8 / 9.5 + 8 / 11) / 5  = 1.080029444...

This goes closer to 1 every time I decrease the step size.