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From User talk:Xor/Better MEA formula
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| Time | User | Activity | Comment |
|---|---|---|---|
| 17:34, 19 September 2017 | Dsekercioglu (talk | contribs) | Comment text edited | |
| 10:38, 18 September 2017 | Dsekercioglu (talk | contribs) | New reply created | (Reply to Why is it better?) |
| 09:46, 18 September 2017 | Xor (talk | contribs) | Comment text edited | (fix) |
| 09:44, 18 September 2017 | Xor (talk | contribs) | Comment text edited | (update) |
| 03:35, 18 September 2017 | Xor (talk | contribs) | Comment text edited | |
| 03:35, 18 September 2017 | Xor (talk | contribs) | Comment text edited | |
| 03:34, 18 September 2017 | Xor (talk | contribs) | New reply created | (Reply to Why is it better?) |
| 03:26, 18 September 2017 | Beaming (talk | contribs) | New thread created |
Is it more precise? or faster to calculate according to this approximation?
Also the bullet speed can go as low as 11, so discrepancy will be even higher at lower values.
By "better", I mean the traditional MEA is wrong. However I can't prove my formula is correct either.
Anyway, it is better, because it is always greater than the traditional one (while conforming to the Game Physics). Therefore closer to the theoretical MEA.
It turns out that I'm wrong. Anyway the updated calculation is useful for surfers — especially when you need to retreat and there is more than one wave.
- Don't worry about the formula returning small values. My brute force MEA returns a lower value than asin which is completely wrong but higher than the full orbit MEA 8 / Vb.
- Traditional mea is wrong because the wave can hit when going directly to the target point which is calculated by MEA.
Dsekercioglu (talk)
