Sorry for being all pedantic about it, but I just wanted to make sure you understood that XOR isn't an inequality check.
if you have two numbers say:
then c=a^b; sets each bit of c to 1 iff that bit in a is one or that bit in b is 1 but not both. Otherwise the bit is set to 0. So c==0011011 is true.
Again. Sorry for being pedantic but I wanted to make sure that this was clear.