Fragment of a discussion from Talk:Yatagan/Source
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Sorry for being all pedantic about it, but I just wanted to make sure you understood that XOR isn't an inequality check.

if you have two numbers say:



then c=a^b; sets each bit of c to 1 iff that bit in a is one or that bit in b is 1 but not both. Otherwise the bit is set to 0. So c==0011011 is true.

Again. Sorry for being pedantic but I wanted to make sure that this was clear.

AW (talk)19:02, 6 June 2013


Sheldor (talk)20:26, 6 June 2013