Why is it better?

Fragment of a discussion from User talk:Xor/Better MEA formula
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By "better", I mean the traditional MEA is wrong. However I can't prove my formula is correct either.

Anyway, it is better, because it is always greater than the traditional one. Therefore closer to the theoretical MEA.

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*Don't worry about the formula returning small values. My brute force MEA returns a lower value than asin which is completely wrong but higher than the full orbit MEA 8 / Vb. 
*Traditional mea is wrong because the wave can hit when going directly to the target point which is calculated by MEA.

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