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Fragment of a discussion from User talk:Dsekercioglu/MEA
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  • Actually, I'm not sure that Traditional MEA is correct. It assumes that the bot doesn't change it's move angle until the wave hits. Because of that you can't get a MEA higher than Pi / 2 with Traditional MEA formula. When you move orbitally, lateralVelocity / (bulletSpeed + advancingVelocity) is the formula that will give you the EA so you can get a EA higher than Pi / 2.
Dsekercioglu (talk)17:09, 24 September 2017

You can't get escape angle higher than Pi/2 by the traditional formula simply because it is impossible.

If your formula can, it must be wrong.

Xor (talk)17:12, 24 September 2017
Found it!
It should be sin(a) / (v / 8 - cos(a) / 2).
Dsekercioglu (talk)17:15, 24 September 2017

The only correct formula to calculate the escape angle of orbital movement where <math>v_{retreat}</math> is not zero is using integral.

Anything else is wrong.

Xor (talk)17:18, 24 September 2017
 
I found a formula higher than Traditional MEA and this one should be correct.
Math.asin(Math.sin(angle) / (bulletSpeed / 8 - Math.cos(angle) / 2))
Dsekercioglu (talk)17:19, 24 September 2017

Anything higher than traditional formula is obviously wrong.

Xor (talk)17:21, 24 September 2017

I don't think that this one is wrong. I only added advancing velocity to the Traditional MEA which shouldn't break anything with the calculations.

Dsekercioglu (talk)17:26, 24 September 2017

No, advancing velocity makes distance not constant, therefore you mast use integral.

Xor (talk)01:44, 25 September 2017